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7p^2+26p+15=0
a = 7; b = 26; c = +15;
Δ = b2-4ac
Δ = 262-4·7·15
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-16}{2*7}=\frac{-42}{14} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+16}{2*7}=\frac{-10}{14} =-5/7 $
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